Optimal. Leaf size=182 \[ \frac {9 b \sin (a+b x)}{4 d^2 \sqrt [3]{c+d x}}+\frac {9 i b e^{i \left (a-\frac {b c}{d}\right )} \sqrt [3]{-\frac {i b (c+d x)}{d}} \Gamma \left (\frac {2}{3},-\frac {i b (c+d x)}{d}\right )}{8 d^2 \sqrt [3]{c+d x}}-\frac {9 i b e^{-i \left (a-\frac {b c}{d}\right )} \sqrt [3]{\frac {i b (c+d x)}{d}} \Gamma \left (\frac {2}{3},\frac {i b (c+d x)}{d}\right )}{8 d^2 \sqrt [3]{c+d x}}-\frac {3 \cos (a+b x)}{4 d (c+d x)^{4/3}} \]
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Rubi [A] time = 0.20, antiderivative size = 182, normalized size of antiderivative = 1.00, number of steps used = 5, number of rules used = 3, integrand size = 16, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.188, Rules used = {3297, 3307, 2181} \[ \frac {9 i b e^{i \left (a-\frac {b c}{d}\right )} \sqrt [3]{-\frac {i b (c+d x)}{d}} \text {Gamma}\left (\frac {2}{3},-\frac {i b (c+d x)}{d}\right )}{8 d^2 \sqrt [3]{c+d x}}-\frac {9 i b e^{-i \left (a-\frac {b c}{d}\right )} \sqrt [3]{\frac {i b (c+d x)}{d}} \text {Gamma}\left (\frac {2}{3},\frac {i b (c+d x)}{d}\right )}{8 d^2 \sqrt [3]{c+d x}}+\frac {9 b \sin (a+b x)}{4 d^2 \sqrt [3]{c+d x}}-\frac {3 \cos (a+b x)}{4 d (c+d x)^{4/3}} \]
Antiderivative was successfully verified.
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Rule 2181
Rule 3297
Rule 3307
Rubi steps
\begin {align*} \int \frac {\cos (a+b x)}{(c+d x)^{7/3}} \, dx &=-\frac {3 \cos (a+b x)}{4 d (c+d x)^{4/3}}-\frac {(3 b) \int \frac {\sin (a+b x)}{(c+d x)^{4/3}} \, dx}{4 d}\\ &=-\frac {3 \cos (a+b x)}{4 d (c+d x)^{4/3}}+\frac {9 b \sin (a+b x)}{4 d^2 \sqrt [3]{c+d x}}-\frac {\left (9 b^2\right ) \int \frac {\cos (a+b x)}{\sqrt [3]{c+d x}} \, dx}{4 d^2}\\ &=-\frac {3 \cos (a+b x)}{4 d (c+d x)^{4/3}}+\frac {9 b \sin (a+b x)}{4 d^2 \sqrt [3]{c+d x}}-\frac {\left (9 b^2\right ) \int \frac {e^{-i (a+b x)}}{\sqrt [3]{c+d x}} \, dx}{8 d^2}-\frac {\left (9 b^2\right ) \int \frac {e^{i (a+b x)}}{\sqrt [3]{c+d x}} \, dx}{8 d^2}\\ &=-\frac {3 \cos (a+b x)}{4 d (c+d x)^{4/3}}+\frac {9 i b e^{i \left (a-\frac {b c}{d}\right )} \sqrt [3]{-\frac {i b (c+d x)}{d}} \Gamma \left (\frac {2}{3},-\frac {i b (c+d x)}{d}\right )}{8 d^2 \sqrt [3]{c+d x}}-\frac {9 i b e^{-i \left (a-\frac {b c}{d}\right )} \sqrt [3]{\frac {i b (c+d x)}{d}} \Gamma \left (\frac {2}{3},\frac {i b (c+d x)}{d}\right )}{8 d^2 \sqrt [3]{c+d x}}+\frac {9 b \sin (a+b x)}{4 d^2 \sqrt [3]{c+d x}}\\ \end {align*}
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Mathematica [A] time = 0.05, size = 125, normalized size = 0.69 \[ \frac {i b e^{-\frac {i (a d+b c)}{d}} \left (e^{2 i a} \sqrt [3]{-\frac {i b (c+d x)}{d}} \Gamma \left (-\frac {4}{3},-\frac {i b (c+d x)}{d}\right )-e^{\frac {2 i b c}{d}} \sqrt [3]{\frac {i b (c+d x)}{d}} \Gamma \left (-\frac {4}{3},\frac {i b (c+d x)}{d}\right )\right )}{2 d^2 \sqrt [3]{c+d x}} \]
Antiderivative was successfully verified.
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fricas [A] time = 0.91, size = 183, normalized size = 1.01 \[ \frac {{\left (-9 i \, b d^{2} x^{2} - 18 i \, b c d x - 9 i \, b c^{2}\right )} \left (\frac {i \, b}{d}\right )^{\frac {1}{3}} e^{\left (\frac {i \, b c - i \, a d}{d}\right )} \Gamma \left (\frac {2}{3}, \frac {i \, b d x + i \, b c}{d}\right ) + {\left (9 i \, b d^{2} x^{2} + 18 i \, b c d x + 9 i \, b c^{2}\right )} \left (-\frac {i \, b}{d}\right )^{\frac {1}{3}} e^{\left (\frac {-i \, b c + i \, a d}{d}\right )} \Gamma \left (\frac {2}{3}, \frac {-i \, b d x - i \, b c}{d}\right ) - 6 \, {\left (d x + c\right )}^{\frac {2}{3}} {\left (d \cos \left (b x + a\right ) - 3 \, {\left (b d x + b c\right )} \sin \left (b x + a\right )\right )}}{8 \, {\left (d^{4} x^{2} + 2 \, c d^{3} x + c^{2} d^{2}\right )}} \]
Verification of antiderivative is not currently implemented for this CAS.
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giac [F] time = 0.00, size = 0, normalized size = 0.00 \[ \int \frac {\cos \left (b x + a\right )}{{\left (d x + c\right )}^{\frac {7}{3}}}\,{d x} \]
Verification of antiderivative is not currently implemented for this CAS.
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maple [F] time = 0.08, size = 0, normalized size = 0.00 \[ \int \frac {\cos \left (b x +a \right )}{\left (d x +c \right )^{\frac {7}{3}}}\, dx \]
Verification of antiderivative is not currently implemented for this CAS.
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maxima [A] time = 1.82, size = 137, normalized size = 0.75 \[ -\frac {{\left ({\left ({\left (i \, \sqrt {3} - 1\right )} \Gamma \left (-\frac {4}{3}, \frac {i \, {\left (d x + c\right )} b}{d}\right ) + {\left (-i \, \sqrt {3} - 1\right )} \Gamma \left (-\frac {4}{3}, -\frac {i \, {\left (d x + c\right )} b}{d}\right )\right )} \cos \left (-\frac {b c - a d}{d}\right ) + {\left ({\left (\sqrt {3} + i\right )} \Gamma \left (-\frac {4}{3}, \frac {i \, {\left (d x + c\right )} b}{d}\right ) + {\left (\sqrt {3} - i\right )} \Gamma \left (-\frac {4}{3}, -\frac {i \, {\left (d x + c\right )} b}{d}\right )\right )} \sin \left (-\frac {b c - a d}{d}\right )\right )} \left (\frac {{\left (d x + c\right )} b}{d}\right )^{\frac {4}{3}}}{4 \, {\left (d x + c\right )}^{\frac {4}{3}} d} \]
Verification of antiderivative is not currently implemented for this CAS.
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mupad [F] time = 0.00, size = -1, normalized size = -0.01 \[ \int \frac {\cos \left (a+b\,x\right )}{{\left (c+d\,x\right )}^{7/3}} \,d x \]
Verification of antiderivative is not currently implemented for this CAS.
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sympy [F] time = 0.00, size = 0, normalized size = 0.00 \[ \int \frac {\cos {\left (a + b x \right )}}{\left (c + d x\right )^{\frac {7}{3}}}\, dx \]
Verification of antiderivative is not currently implemented for this CAS.
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